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18x^2-x-35=0
We add all the numbers together, and all the variables
18x^2-1x-35=0
a = 18; b = -1; c = -35;
Δ = b2-4ac
Δ = -12-4·18·(-35)
Δ = 2521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{2521}}{2*18}=\frac{1-\sqrt{2521}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{2521}}{2*18}=\frac{1+\sqrt{2521}}{36} $
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